Area bounded by curves

**maybeline9216** · October 11th 2008, 06:32 AM

Please do part(ii).My answer is 5.61% but the paper's answer is 5.31%.
Please check for me thanks...

**skeeter** · October 11th 2008, 07:02 AM

I get 5.31%

**maybeline9216** · October 11th 2008, 07:06 AM

Can tell me how u get? Like: what is your value for the shaded and unshaded area respectively, area of region OAPB, coords.of B AND Coords.of Q

I want to see where my workings and answer differ...

**skeeter** · October 11th 2008, 07:40 AM

show me what you did ... maybe i can see your mistake.

**maybeline9216** · October 11th 2008, 07:51 AM

Originally Posted by skeeter

show me what you did ... maybe i can see your mistake.

Please look at my qn 11 workings.Thanks

**skeeter** · October 11th 2008, 01:27 PM

let $f(x) = e^x$
$g(x) = 4 - e^x$
$h(x) = 2(x - \ln{2}) + 2$

$A = \int_0^{\ln{2}} f(x) \, dx + \int_{\ln{2}}^{\ln{4}} g(x) \, dx$

$B = \int_0^{\ln{2}} f(x) - h(x) \, dx$

calculate $\frac{B}{A}$ .

**maybeline9216** · October 11th 2008, 07:51 PM

Thanks i found my mistake already..i forgot to add the unshaded area into the calculation of the area of the whole plot

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