Differention with repeat to x cot^-1(x) Answer: -2/(Squar root (1-9X^2) i stuck...
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Originally Posted by sanikui Differention with repeat to x cot^-1(x) Answer: -2/(Squar root (1-9X^2) i stuck... Use integration by parts: .
Originally Posted by mr fantastic Use integration by parts: . My mistake. I misread differentiate as integrate. Now differentiate both sides wrt x (use the chain rule on the left hand side) and then make dy/dx the subject.
ok i try.
Originally Posted by mr fantastic My mistake. I misread differentiate as integrate. Now differentiate both sides wrt x (use the chain rule on the left hand side) and then make dy/dx the subject. Spoilers in white: Using the chain rule: Note that:
Finaly noe how to do this question. V^^ Let x=coty x=1 over tany tany= 1 over x y= tan(1 over x) From there i can do liaw....thx alot ^^
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