Find arc length
x=t^2, y=4t^3-1 -1<t<1
dx/dt=2t dy/dt= 12t^2
integral from -1 to 1 sq root (4t^2 +144t^4)dt
then, integral from -1 to 1 2t*sq root (1+36t^2)dt
Please help me find the answer. I know i have to use trig substitution does u=6tantheta?