Okay, so I've tried doing this problem a million times and I can't seem to get the right answer. It seems fairly straight forward.

Here is the question:

Iff(x)=6(sin(x))x, findf(3)

So this is what I've tried:

lny=6xlnsinx

(1/y)(y')=f'g+fg'

(1/y)(y')=(6)(lnsinx)+[(6x)((cosx)/(sinx))]

y'=[(6lnsin(x))+(6xcot(x))]*(6(sin(x))^x)

So I tried pluggin in 3 to the answer, but it does not give me the correct answer.

Am I doing something wrong?

(I've also tried with the assumption that lny=xln6sinx, but that didn't work either.

Thanx!