Here's the problem I'm having.

f(x)=ax^n, where n and a are constants and f'(2)=3 and f'(4)= 24

I'm totally confused as to what I should be doing of even what the first steps should be. Any help is greatly appreciated.

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- Oct 10th 2008, 06:28 PM_nysaA derivative problem?
Here's the problem I'm having.

f(x)=ax^n, where n and a are constants and f'(2)=3 and f'(4)= 24

I'm totally confused as to what I should be doing of even what the first steps should be. Any help is greatly appreciated. - Oct 10th 2008, 06:35 PMJhevon
- Oct 10th 2008, 06:39 PM_nysaQuote:

they want you to find the constants a and n

find the derivative, then, plug in the values as prescribed. you will obtain two equations in a and n that you can solve simultaneously

a(nx^n-1)

And this is the part where I get confused, because I don't know what values go where. - Oct 10th 2008, 06:45 PMChris L T521
A similar problem was done here.

--Chris - Oct 10th 2008, 07:07 PM_nysa
Thanks Chris, but I'm stuck again.

I followed the example that you linked too, and this is what I got to.

1/8 = (1/8)^-1(1/8)^n

And then I don't know what to do anymore. - Oct 10th 2008, 07:17 PMChris L T521
- Oct 10th 2008, 07:29 PM_nysa
Yes I can, thanks so much!