Hi can someone please help me with this:

lim $\displaystyle \frac{sin^2(4x)}{x^2}$

x->0

I know by finding derivative of the function I get:

$\displaystyle \frac{4x^2cos^2(4x) - 2xsin^2(4x)}{x^4}$

(hopefully that's right so far)

what do I do next? is there a trig I identity that I can use to simplify or something?

thanks!