Thanks

Yes, normal is different to normalized/unit

I've got a somewhat related question about ellipsoids..

$\displaystyle {x^2 \over a^2}+{y^2 \over b^2}+{z^2 \over c^2} - 1 = 0$

If I'm trying to find a point on its surface that is in a direction v what do I need to do?

For a sphere centred at p with radius r it is just:

$\displaystyle {p + r{v \over \| v \|}}$