1. ## Paramters

Sketch the curve by eliminating the parameter, and indicate the direction of increasing t

x=sec^2t
y=tan^2t

I don't know how I would isolate t. Do i use the inverse? But what angle do i use?

Help is greatly appreciated

2. Originally Posted by Khaali91
Sketch the curve by eliminating the parameter, and indicate the direction of increasing t

x=sec^2t
y=tan^2t

I don't know how I would isolate t. Do i use the inverse? But what angle do i use?

Help is greatly appreciated
Are you familiar with the identity $\sin^2 t + \cos^2 t = 1 \Rightarrow \tan^2 t + 1 = \sec^2 t$ ....

3. ## ?

so would it be:

Tan^2t= x+1
Tan^2t=y

y=x+1

? im really confused

4. Originally Posted by Khaali91
so would it be:

Tan^2t= x+1
Tan^2t=y

y=x+1

? im really confused
No.

$\tan^2 t + 1 = \sec^2 t \Rightarrow 1 = \sec^2 t - \tan^2 t$.

And you're told $x = \sec^2 t$ and $y = \tan^2 t$.

I hope you can see what to do now.

5. yea i got it thank you.

x-y= Sec^2t-Tan^2t
x-y=1

Thank You