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Math Help - Paramters

  1. #1
    Junior Member Khaali91's Avatar
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    Paramters

    Sketch the curve by eliminating the parameter, and indicate the direction of increasing t

    x=sec^2t
    y=tan^2t

    I don't know how I would isolate t. Do i use the inverse? But what angle do i use?

    Help is greatly appreciated
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  2. #2
    Flow Master
    mr fantastic's Avatar
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    Quote Originally Posted by Khaali91 View Post
    Sketch the curve by eliminating the parameter, and indicate the direction of increasing t

    x=sec^2t
    y=tan^2t

    I don't know how I would isolate t. Do i use the inverse? But what angle do i use?

    Help is greatly appreciated
    Are you familiar with the identity \sin^2 t + \cos^2 t = 1 \Rightarrow \tan^2 t + 1 = \sec^2 t ....
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  3. #3
    Junior Member Khaali91's Avatar
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    ?

    so would it be:

    Tan^2t= x+1
    Tan^2t=y

    y=x+1

    ? im really confused
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  4. #4
    Flow Master
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    Quote Originally Posted by Khaali91 View Post
    so would it be:

    Tan^2t= x+1
    Tan^2t=y

    y=x+1

    ? im really confused
    No.

    \tan^2 t + 1 = \sec^2 t \Rightarrow 1 = \sec^2 t - \tan^2 t.


    And you're told x = \sec^2 t and y = \tan^2 t.


    I hope you can see what to do now.
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  5. #5
    Junior Member Khaali91's Avatar
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    yea i got it thank you.

    x-y= Sec^2t-Tan^2t
    x-y=1

    Thank You
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