i still cant get the correct answer for this,i simply equated coefficients etc anad got as far as the first two terms in the answer. The question is basically

Q express $\displaystyle \frac{x^5-1}{x^2(x^3+1)}$ in partial fractions ?[/quote]$\displaystyle \frac{x^5-1}{x^5+x^2}$

supposed working,,

$\displaystyle \frac{x^5-1+x^2-x^2}{x^5+x^2}$

$\displaystyle \frac{x^5+x^2}{x^5+x^2}-\frac{1+x^2}{x^5+x^2}$

$\displaystyle 1-\frac{1+x^2}{x^2(x^3+1)}$

I'd start it that way. You can try and finish it.

In this case:

$\displaystyle 1+x^2\equiv(Ax+B)(x^3+1)+(Cx^2+Dx+E)(x^2)$

Since this is an identity, it is true for all values of x (this is a great help in determing the values of A,B,C,D and E!).[/quote] i miust be doing something awfully wrong