In this problem, find the equation of the graph which passes through the given point and has the indicated slope:
m = y' = dy/dx = (2y)/(3x)
So, after cross multiplying to separate, I have:
(1/2y) (dy) = (1/3x) (dx)
After integrating both sides:
Ln(y)/2 = Ln(x)/3
Ln(y) = (2Ln(x))/3
Is this the right track? I can't remember how to get rid of the Ln on the left side to solve for y. How do I use the point (1,1) ?
Thank you so much!!