partial fractions

**tylerd** · October 9th 2008, 01:42 AM

Hi I am trying to solve the following problem: find the constant A0, A1, A2 such that

$\frac{1}{(1+(a0)x^2-i(b0)x)(1+(a1)x^2-i(b1)x)(1+(a2)x^2-i(b2)x)}$
= $\frac{A0}{(1+(a0)x^2-i(b0)x)}$ + $\frac{A1}{(1+(a1)x^2-i(b1)x)}$ + $\frac{A2}{(1+(a2)x^2-i(b2)x)}$

That s drives me mad

! Any help for me please.[/quote]

**p00ndawg** · October 9th 2008, 04:55 AM

Multiply $<br /> \frac{A0}{(1+(a0)x^2-i(b0)x)}$ + $\frac{A1}{(1+(a1)x^2-i(b1)x)}$ + $\frac{A2}{(1+(a2)x^2-i(b2)x)}$

by $({(1+(a0)x^2-i(b0)x)(1+(a1)x^2-i(b1)x)(1+(a2)x^2-i(b2)x)})$

you should be left with this, and solve.

$(A0)(1+(a1)x^2-i(b1)x)(1+(a2)x^2-i(b2)x)$ $+(A1)(1+(a0)x^2-i(b0)x)(1+(a2)x^2-i(b2)x)$
$+(A2)(1+(a0)x^2-i(b0)x)(1+(a1)x^2-i(b1)x)$

**tylerd** · October 9th 2008, 10:40 PM

Hi thank you for your help. However, solving this

=1 then?? but only one equation for 3 unknown constants? How is possible ?

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