Find the points on the curve y= tan x, -pi/2< x < pi/2, where the tangent is parallel to the line y= 2x. How do you do this? I'm really confused
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Originally Posted by JimDavid How do you do this? I'm really confused you want all the points where the derivative has a value of 2. so find the derivative, set it equal to 2 and solve for x
Originally Posted by Jhevon you want all the points where the derivative has a value of 2. so find the derivative, set it equal to 2 and solve for x I turned tan x into sec^2 x, so it's 2=sec^2? How do you suppose to solve for it?
Originally Posted by JimDavid I turned tan x into sec^2 x, so it's 2=sec^2? How do you suppose to solve for it? yes, $\displaystyle \frac d{dx} \tan x = \sec^2 x$ now recall that $\displaystyle \sec x = \frac 1{\cos x}$
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