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Math Help - Derivative of trigonometric

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    Derivative of trigonometric

    Find the points on the curve y= tan x, -pi/2< x < pi/2, where the tangent is parallel to the line y= 2x.
    How do you do this? I'm really confused
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by JimDavid View Post
    How do you do this? I'm really confused
    you want all the points where the derivative has a value of 2. so find the derivative, set it equal to 2 and solve for x
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    Quote Originally Posted by Jhevon View Post
    you want all the points where the derivative has a value of 2. so find the derivative, set it equal to 2 and solve for x
    I turned tan x into sec^2 x, so it's 2=sec^2? How do you suppose to solve for it?
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by JimDavid View Post
    I turned tan x into sec^2 x, so it's 2=sec^2? How do you suppose to solve for it?
    yes, \frac d{dx} \tan x = \sec^2 x

    now recall that \sec x = \frac 1{\cos x}
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