Originally Posted by
khuezy Can i make 1/(x^2) into -1/(((1- ((x-1)^2)+2x)))
and use f(x) = 1/(1-u) where u = ((x-1)^2)+2x))
and get -sigma : ((x-1)^2 + 2x))^n
??
Or is that illegal
How about 1/(x^2) = d/dx [-1/x]
but what is the taylor series for 1/x