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Math Help - Taylor Series partial fractions

  1. #1
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    Taylor Series partial fractions

    f(x) =
    1/
    (2x − 5)^2(3x − 1)based at b = 0.
    I tried partial fractions and I think I'm doing it wrong.
    Thanks in advance.
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  2. #2
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    Quote Originally Posted by khuezy View Post
    f(x) =
    1/
    (2x − 5)^2(3x − 1)based at b = 0.
    I tried partial fractions and I think I'm doing it wrong.
    [snip]
    Then please show your working.
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  3. #3
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    ok

    1 = A(2x-5)(3x-1) + B(3x-1) + C(2x-5)(2x-5)
    x=5/2
    1= B(3(5/2)-1) B=2/13????
    That doesn't seem right.
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  4. #4
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    Quote Originally Posted by khuezy View Post
    1 = A(2x-5)(3x-1) + B(3x-1) + C(2x-5)(2x-5)
    x=5/2
    1= B(3(5/2)-1) B=2/13????
    That doesn't seem right.
    Sorry but I cannot follow this working. Please show all the working, set out clearly. If you expect to get a clear reply to your problem, then surely it's reasonable that you clearly show all your working when requested.
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