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Thread: Derivatives With Square Roots

  1. #1
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    Derivatives With Square Roots

    the problem is:
    if v(t)=sqr root(t^7)-sqr root(t) find the second derivative v"t.

    i differentiated it and came up with 7/2t^5/2 - 1/2t^-1/2. but what does it mean to find the second derivative? and am i even doing it right?
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  2. #2
    Super Member 11rdc11's Avatar
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    You did that correctly. To find your 2nd derivative just take the derivative of your first derivative.
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  3. #3
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    ooo how do i do that?
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  4. #4
    Super Member 11rdc11's Avatar
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    \frac{7t^{\frac{5}{2}}}{2} - \frac{1}{2\sqrt{t}}

    Now take the derivative again using the power rule.

    \bigg(\frac{35}{4}\bigg)t^{\frac{3}{2}}~+~\frac{1}  {4}t^{\frac{-3}{2}}
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