For the following expression I am trying to find a) dy/dx b) d^2y/dx^2 [also denoted f" (x)] y = 2x^3 + 6x^2 -9x + 10 Answers: a) I have found 2x^2 + 4x - 3 Do I have to go further than this? For part b I have no real clues Thanks.
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The answer for a) should be $\displaystyle f'(x) = 6x^2 + 12x - 9$. For b), just take the derivative of f'(x).
brilliant thanks a lot! What does the derivative mean though?
The derivative of a function $\displaystyle y = f(x)$ is $\displaystyle \frac{dy}{dx} = f'(x)$. Some notation you may also have seen is $\displaystyle \frac{d}{dx}f(x)$.
Originally Posted by IronMan brilliant thanks a lot! What does the derivative mean though? it can also be seen as the slope of the original equation.
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