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Math Help - Taylor series ln(1 + x^2)

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    Taylor series ln(1 + x^2)

    ln(1 + x^2)
    how would I do this?
    Thanks in advance.
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  2. #2
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    Quote Originally Posted by khuezy View Post
    ln(1 + x^2)
    how would I do this?
    Thanks in advance.
    Remember \ln (1 + t) = \sum_{n=0}^{\infty} \frac{(-1)^n t^n}{n} for |t|<1.

    Therefore if x^2 < 1 then \ln (1+x^2) = \sum_{n=0}^{\infty} \frac{(-1)^n x^{2n}}{n}
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