lim (1-tanx)/(sinx-cosx) x->pi/4 I had been trying for 20 mins, but still cannot find a way to solve it as both top and bottom goes to 0... Thank you. KK
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Originally Posted by tttcomrader lim (1-tanx)/(sinx-cosx) x->pi/4 I had been trying for 20 mins, but still cannot find a way to solve it as both top and bottom goes to 0... Thank you. KK $\displaystyle \frac{1-\tan(x)}{\sin(x)-\cos(x)} =\frac{1}{-\cos(x)}\frac{(1-tan(x))}{(1-tan(x))}=-\sec(x) $ so: $\displaystyle \lim_{x \to \pi/4} \frac{1-\tan(x)}{\sin(x)-\cos(x)} = \lim_{x \to \pi/4} -\sec(x) $ RonL
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