Hey guys im new here, but I have a test today and I need to understand trig limits better.
lim of x approaching 0
sin(4x)
sin(6x)
the hint that was given was "use the identity Lim x approaching 0
sinx = 1"
x
Hey guys im new here, but I have a test today and I need to understand trig limits better.
lim of x approaching 0
sin(4x)
sin(6x)
the hint that was given was "use the identity Lim x approaching 0
sinx = 1"
x
The derivative is the slope of the tangent line. The equation of a line in point slope form is given by:
$\displaystyle y - y_1 = m(x-x_1)$
Where $\displaystyle (x_1, y_1)$ is the point in question and m is the slope. The equation of the normal line to this line contains $\displaystyle (x_1, y_1)$, but its slope is the negative reciprocal of the original line.
For instance, if line K has a slope of 4, then the line that is perpendicular/normal to line k will have a slope of $\displaystyle -\frac{1}{4}$. Just remember that:
$\displaystyle m_{line} \cdot m_{normal} = -1$