find dy/dx y=xto3(5xto2 +1 )to-2/3

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Originally Posted by homerb find dy/dx y=xto3(5xto2 +1 )to-2/3 If im not wrong, ur "to" is power rite?? Use Product Rule to solve: dy/dx= (x^3) d/dx [(5x^2 + 1)]^(-2/3) + [(5x^2 + 1)]^(-2/3)d/dx(x^3) =[( x^3) x [-2/3{(5x^2 +1)^(-5/3)} x 10x] +[(5x^2 +1)^(-2/3) x 3x^2] = ? (continue on ur own)

Last edited by maybeline9216; October 7th 2008 at 07:43 PM. Reason: forgot something

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