I need help with the following derivative:
sinx^1/3 + (sinx)^1/3
Thanks!
I'm assuming this is $\displaystyle \sin (x^{1/3}) + (\sin x)^{1/3}$.
Take the two parts of the function separately.
The derivative of $\displaystyle \sin (x^{1/3})$ is
$\displaystyle \cos (x^{1/3}) \cdot (1/3)x^{-2/3}$.
The derivative of $\displaystyle (\sin x)^{1/3}$ is
$\displaystyle (1/3)(\sin x)^{-2/3} \cdot \cos x$.
Add the two together and you're done.