find dy/dx
y=xto3(5xto2 =1)to-2/3
You need to use the product rule to compute the derivative.
$\displaystyle x^3(5x^2 + 1)^{-2/3}$
Let $\displaystyle u = x^3$ and $\displaystyle v = (5x^2 + 1)^{-2/3}$.
Then the derivative of the function uv is:
$\displaystyle u \cdot \frac{dv}{dx} + v \cdot \frac{du}{dx}$.
Can you calculate $\displaystyle \frac{du}{dx}$ and $\displaystyle \frac{dv}{dx}$?