Given y= sqr x + ln sqr x, prove that dy/dx = (x + sqr x)/ (2x x sqr x)
Follow Math Help Forum on Facebook and Google+
Originally Posted by maybeline9216 Given y= sqr x + ln sqr x, prove that dy/dx = (x + sqr x)/ (2x x sqr x) $\displaystyle y = x^{1/2} + \ln x^{1/2} = x^{1/2} + \frac{1}{2} \, \ln x$. Where do you get stuck when differentiating? Take care with the simplifying.
Originally Posted by mr fantastic $\displaystyle y = x^{1/2} + \ln x^{1/2} = x^{1/2} + \frac{1}{2} \, \ln x$. Where do you get stuck when differentiating? Take care with the simplifying. Thanks i got it already =)
View Tag Cloud