is this correct? f(x,y)= arctan(y/x) , f(x)= (2,3) so, fx(x,y) = -y/(x^2+y^2) fx(2,3) = -3/(4+9)= -3/13
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Originally Posted by mathlovet is this correct? f(x,y)= arctan(y/x) , f(x)= (2,3) so, fx(x,y) = -y/(x^2+y^2) fx(2,3) = -3/(4+9)= -3/13 Yes . --Chris
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