I'm completely lost with this.

Need to calculate the integral $\displaystyle \int {\frac{{\sin (\sqrt u )}}{{\sqrt u }}du} $ using the substitution $\displaystyle {\rm x = }\sqrt {\rm u}$

As far as I am getting is this

$\displaystyle

\begin{array}{l}

= \int {\frac{{\sin (x)}}{x}du} \\

= \int {\frac{1}{x}\sin (x)du} \\

\end{array}

$

and that $\displaystyle dx = \frac{1}{2}u^{\frac{{ - 1}}{2}} du$

Could someone solve and try and explain method. thanks