You found the slope of the tangent line to be 1/2 = 0.5. Let . Then the tangent line can be expressed as . But so the line is . You have to calculate the value of the function .
first i had to find the derivation of a function, and i found that to be
g'(t)= 2/(t+3)^2
now i'm asked to find the equation of the tangent line when t = -5
so i figured id plug -5 into the above equation and i ended up with:
2/(-5+3)^2= 1/2
So that means i have two points an x and a y
-5,1/2
This is where im stuck how can i find a slope with this information so i can write on the tangent equation?