first i had to find the derivation of a function, and i found that to be

g'(t)= 2/(t+3)^2

now i'm asked to find the equation of the tangent line when t = -5

so i figured id plug -5 into the above equation and i ended up with:

2/(-5+3)^2= 1/2

So that means i have two points an x and a y

-5,1/2

This is where im stuck how can i find a slope with this information so i can write on the tangent equation?