Results 1 to 4 of 4

Math Help - Tangent line and velocity problems

  1. #1
    Newbie
    Joined
    Sep 2008
    Posts
    24

    Tangent line and velocity problems

    I'm having some trouble with some of these. It's kinda one of those times where you're doing great in class and then you leave and can't remember anything

    1. If a rock is thrown in the air on a small planet with velocity 25 m/s, its height in meters is Y = 25t - 4.9t^2. What is the rock's velocity at t = 3?

    2. The slope of the tangent line to the curve Y = 4(sqrt[x]) is _______. The equation for the line is Y = mx + b, where M is ______ and B is ______.
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Joined
    Jun 2008
    From
    North Texas
    Posts
    11,698
    Thanks
    454
    1. If a rock is thrown in the air on a small planet with velocity 25 m/s, its height in meters is Y = 25t - 4.9t^2. What is the rock's velocity at t = 3?

    v = \frac{dy}{dt}

    2. The slope of the tangent line to the curve Y = 4(sqrt[x]) is _______. The equation for the line is Y = mx + b, where M is ______ and B is ______.

    slope = \frac{dy}{dx}, the derivative of y = 4\sqrt{x}

    second sentence blanks are from algebra 1 ... don't make it out to be harder than it is. what does m represent? b ??
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Sep 2008
    Posts
    24
    Ok thanks. Now what would I do with:

    Find f'(t) for f(t) = 12/(t^6)

    and

    Find f'(t) for f(t) = (3x)^5
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Super Member
    earboth's Avatar
    Joined
    Jan 2006
    From
    Germany
    Posts
    5,830
    Thanks
    123
    Quote Originally Posted by john11235 View Post
    Ok thanks. Now what would I do with:

    Find f'(t) for f(t) = 12/(t^6)

    and

    Find f'(t) for f(t) = (3x)^5
    1. If you have a new question, please start a new thread.

    2. Re-write

    f(t)=\dfrac{12}{t^6} = 12 \cdot t^{-6}

    Calculate f'(t)=\dfrac{df}{dt} as usual but keep in mind that -6 - 1 = -7

    The second question is a trick question:

    f(t) states that the variable is t. Therefore (3x)^5 is a constant here. And therefore f'(t)=0
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. tangent line problems
    Posted in the Calculus Forum
    Replies: 5
    Last Post: November 22nd 2011, 01:53 PM
  2. Replies: 3
    Last Post: November 4th 2011, 06:42 PM
  3. Replies: 6
    Last Post: January 12th 2011, 02:38 PM
  4. Velocity and Normal line problems
    Posted in the Calculus Forum
    Replies: 7
    Last Post: June 9th 2010, 06:02 PM
  5. Limits: Tangent and Velocity Problems
    Posted in the Calculus Forum
    Replies: 1
    Last Post: September 1st 2009, 07:16 AM

Search Tags


/mathhelpforum @mathhelpforum