# Math Help - A troubling limit

1. ## A troubling limit

The question is

lim x-> 0 from the right side

It says prove that the limit of

sqrt(x) * e^{sin(pi/x)} = 0
That's square root x multiplied by e to the power of sin(pi/x)

Says to prove this....The "squeeze" theorem appears in this section so it might be related to that...But where to start? with -1 < sin[pi/x] < 1?

2. $\frac {1}{e} \le e^{\pi/x} \le e$