The question is
lim x-> 0 from the right side
It says prove that the limit of
sqrt(x) * e^{sin(pi/x)} = 0
That's square root x multiplied by e to the power of sin(pi/x)
Says to prove this....The "squeeze" theorem appears in this section so it might be related to that...But where to start? with -1 < sin[pi/x] < 1?