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Math Help - A troubling limit

  1. #1
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    A troubling limit

    The question is

    lim x-> 0 from the right side

    It says prove that the limit of

    sqrt(x) * e^{sin(pi/x)} = 0
    That's square root x multiplied by e to the power of sin(pi/x)

    Says to prove this....The "squeeze" theorem appears in this section so it might be related to that...But where to start? with -1 < sin[pi/x] < 1?
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  2. #2
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    \frac {1}{e} \le e^{\pi/x} \le e
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