Here is the question:

For the function

g(t)=2/t+3

Using the limit definition of the derivative find g'(t)

Ive gotten this far:

g'(t)=lim h->0 g(t+h) -g(t)/h

=lim h->0 2/t+h+3 - 2/t+3 all over h

=lim h->0 2t+6 -(2t+2h+6)/(t+3)(t+h+3) all over h

and I got that down to this:

-2h/(t+3)(t+h+3) all over h

This is where i am stuck. Help please!