Find the Limit.

lim x->oo sqrt(x^2+1)

oo=infinity

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- Oct 4th 2008, 07:36 PMjohntuanlimits
Find the Limit.

lim x->oo sqrt(x^2+1)

oo=infinity - Oct 4th 2008, 07:37 PMThePerfectHacker
- Oct 4th 2008, 07:43 PMjohntuan
how come the 1 turns to a 0?

- Oct 4th 2008, 07:44 PMThePerfectHacker
It does not. It use "$\displaystyle \geq$" there.

Basically I am showing that $\displaystyle \sqrt{x^2+1}$ is larger than $\displaystyle x$. And since $\displaystyle x$ goes to $\displaystyle \infty$ must mean $\displaystyle \sqrt{x^2+1}$ goes to $\displaystyle \infty$.