When I take the derivative of sin(2x+3), I have cos(2x+3)2 or 2cos(2x+3) Would someone tell me what to do with taking a derivative of sin((2x+3)/5)? Do I treat it as a quotient rule or what?
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You can use the quotient rule to calculate the derivative of $\displaystyle \frac{2x + 3}{5}$, but it's easier to write it as $\displaystyle \frac{2}{5}x + \frac{3}{5}$ and calculate the derivative of that.
That' great! so 2/5cos((2x+3)/5) If it is y=(2sin2x)/(x+3), there is no alternative but the quotient rule?
In the last problem, you have no option but the quotient rule, that I know of yet.
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