I was hoping someone could double-check this for me:

Find the volume of a solid obtained by rotating the region bounded by y = x^2 + 1 , y = 9 - x ^2, about y = -1.

(Sorry I don't know how to use the symbols, so this may be hard to read)

pi integral from -5 to 5 ( ( 1+ 9-x^2)^2 - ( 1 + x^2 + 1 )^2) dx

After some algebra...

pi (96 x - (4/3) x ^3) from -5 to 5

626.66 pi

Not sure if I am doing this correctly, would appreciate some feedback.