1. Show lim Θ/sinΘ=1
Θ->0
(Hint: show sinΘcosΘ <Θ<tanΘ)
I have no idea to do this problem, other than use the squeeze theorem, but i still dont know what to do. any help would be greatly appreciated.
1. Show lim Θ/sinΘ=1
Θ->0
(Hint: show sinΘcosΘ <Θ<tanΘ)
I have no idea to do this problem, other than use the squeeze theorem, but i still dont know what to do. any help would be greatly appreciated.
here is a link to the classical geometric approach in determining this limit ...
http://www.csun.edu/~ac53971/courses/math350/xtra_sine.pdf
I will show my own proof for this.
Proof.
First draw a unit circle, and put a equilateral-polygon in it.
Then from the center of the circle, draw lines to the corners of the polygon.
We see that the center angleis divided to
, thus all the triangles have
as the vertex of the isosceles triangle, and each triangles have the area
.
Hence the sum of the areas of the triangles is.
We can see that lettingtend to infinity
tends to the are a of the circle
.
That is
or equivalently
.
Substitute, then we see that
as
, which yields
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I hope this is helpful.
Note. Here,travels through rational numbers and since
means accumulation, we may think that
travels through reals since it is the closure of rational numbers.