lim.....asinx-sin2x/tan^3x is finite,find the value of 'a' and find the limit.
x->0
I'm assuming that this is your limit expression ...
using L'Hopital ...
at this point, substituting 0 in the denominator yields 0 and substituting 0 in the numerator yields (a - 2). for the limit to exist, a must equal 2.
starting from scratch with a = 2 ...