Notice that on the interval [0,1], sqrt(x) - 1 is less than 0 or equal to zero, and from [1, 4] it is greater than or equal to zero. Then you can split the integral into two, and then get rid of absolute value. Remember that:
Provided that
Hi guys
I've been doing some practice problems on integration and this particular one stumped me.
Int(|sqrt(x)-1|.dx)
Evaluate the integral at (0,4).
So far I've gotten this when x>1, sqrt(x)-1>0, so the integral is 2/3.x^(3/2)-x+C. I'm still stuck on the (0,1) portion.
I'm a little rusty at integration so any advice would be appreciated.
Thanks.