Help finding surface area of a surface
Suppose the curve defined by y=4x^(1/2) for x <= x <= 1 is revolved about the x-axis.
1.) Find the surface area of the surface.
S= 2PI ∫ r(x) [sqrt of 1 + (f'x)]^2
=2PI∫ 4x^1/2 [sqrt of 1 + 2x^3/2]^2
Have I come anywhere close to doing this problem correctly? I'm thinking I might have done something wrong. If I have, can someone show me what I did wrong or how to do this problem correctly? Thanks