I can't seem to be able to figure this one out. Could someone walk me through it? Find an equation for the line tangent to the graph of at the point for . =
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show me the derivative ...
2x(e^x)+(e^x)(2)
note that it can also be written as $\displaystyle f'(x) = 2e^x(x+1)$ for $\displaystyle f(x) = 2xe^x$ , $\displaystyle f(1) = 2e$ $\displaystyle f'(1) = 4e$ $\displaystyle y - 2e = 4e(x - 1)$ that's all folks.
thank u so very much skeeter. Ur a life saver!!!!!!!!
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