Implicit Differentation

**cjmac87** · October 3rd 2008, 02:23 PM

$e^y+24-e^-1 = 5x^2+4y^2$

I can't figure this out....

I believe this stage is correct $e^y+e^-1=10x+8y*y'-y'$

But Need help on further solving it.

Help appreciate.

**icemanfan** · October 3rd 2008, 02:25 PM

Actually the first step should be $y'e^y = 10x + 8yy'$

**cjmac87** · October 3rd 2008, 02:27 PM

Where did you put the $e^-1$ ?

**icemanfan** · October 3rd 2008, 02:28 PM

$e^{-1}$ is a constant and its derivative is 0.

**cjmac87** · October 3rd 2008, 02:34 PM

I thought it was -e^-1.

Anyway, in case of constant I get $(10x)/(-1*e^y-8y)$ . Where could I have gone wrong there?

**icemanfan** · October 3rd 2008, 02:45 PM

I get $y' = \frac{10x}{e^y - 8y}$

**cjmac87** · October 3rd 2008, 02:47 PM

The reason i have negative 1 is because there are two y', and when i place it ont he other side (-y') I factored and assumed 1. Why is this not correct?

Thanks however.

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