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Math Help - Tangen Line Equation Problem???

  1. #1
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    Tangen Line Equation Problem???

    Find an equation for the line tangent to the graph of
    at the point (2, 0.857142857142857).
    =
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  2. #2
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    see this thread ...

    http://www.mathhelpforum.com/math-he...gent-line.html

    btw, why the decimal for \frac{6}{7} ?

    you uncomfortable with fractions?
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  3. #3
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    this is what they gave me in the problem
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  4. #4
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    I tried to use that link but i am still coming up with the wrong answer.

    could someone possible walk me through it?
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  5. #5
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    what did you get for the derivative of f(x)?
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  6. #6
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    15/(x+5)^2
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  7. #7
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    good.

    the slope of the tangent line is f'(2) = \frac{15}{(2+5)^2} = \frac{15}{49}

    use the point-slope form for a linear equation ...

    y - \frac{6}{7} = \frac{15}{49}(x - 2)

    this is the tangent line equation in point-slope form.

    if you need to change it to standard form, multiply both sides by 49 to clear the fractions and manipulate accordingly.
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  8. #8
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    Thanks again skeeter. I was so close!!!
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