1. equation tangent line

find an equation for the tangent line to the given curve at the point where x=x0. y=(6x-5)(3+3x); x0=0

2. $x_0 = 0$
$y_0 = -15$

find the derivative of $y$, then find $y'(x_0)$, the slope of the line tangent to the curve at $(x_0,y_0)$.

now use the point-slope form of a linear equation to find the equation of the tangent line.

$y - y_0 = y'(x_0)(x - x_0)$