y = (e^x*logx)/log(2x+1)
y' = (log(2x+1)(e^x*logx + e^x*1/x) - (e^x*logx)(2/2x+1))/(log(2x+1))^2
is that correct? thanks u
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Yes, you are right.
Originally Posted by Chop Suey Yes, you are right.
thank u, much appreciated!
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