Thread: derivative

y = (e^x*logx)/log(2x+1)

y' = (log(2x+1)(e^x*logx + e^x*1/x) - (e^x*logx)(2/2x+1))/(log(2x+1))^2


is that correct? thanks u

Yes, you are right.

Originally Posted by Chop Suey

Yes, you are right.

thank u, much appreciated!