y = (e^x*logx)/log(2x+1)

y' = (log(2x+1)(e^x*logx + e^x*1/x) - (e^x*logx)(2/2x+1))/(log(2x+1))^2

is that correct? thanks u

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- Oct 2nd 2008, 06:24 AMjvignacioderivative
y = (e^x*logx)/log(2x+1)

y' = (log(2x+1)(e^x*logx + e^x*1/x) - (e^x*logx)(2/2x+1))/(log(2x+1))^2

is that correct? thanks u - Oct 2nd 2008, 06:33 AMChop Suey
Yes, you are right.

- Oct 2nd 2008, 06:36 AMjvignacio