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Math Help - [SOLVED] Partial derivation

  1. #1
    Newbie kirbyiwaki's Avatar
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    Unhappy [SOLVED] Partial derivation

    I'm new at this, so...
    yln{x}\ln{y}dx+dy=0

    then, making it a function:

    f(x,y)=\frac{dy}{dx}= -yln{x}\ln{y}

    \frac{\partial{f}}{\partial{y}}= ?

    any help (and further explanations) will be great...

    thanks in advance ^^
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  2. #2
    Moo
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    Hello,
    Quote Originally Posted by kirbyiwaki View Post
    I'm new at this, so...
    yln{x}\ln{y}dx+dy=0

    then, making it a function:

    f(x,y)=\frac{dy}{dx}= -yln{x}\ln{y}

    \frac{\partial{f}}{\partial{y}}= ?

    any help (and further explanations) will be great...

    thanks in advance ^^
    In other words, you're asked for the partial derivative of -y \ln(x) \ln(y), with respect to y.

    This means that you have to consider x as a constant. Thus \ln(x) will be treatead as a constant. If you can't see it, substitute it by k.

    g(y)=-k \cdot y\ln(y)

    Can you find g'(y) ?
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  3. #3
    Newbie kirbyiwaki's Avatar
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    OMG, that was easy xD... looks like the \ln scared me >_>... thanks n__n"
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