# Math Help - Improper Integral discontinuity

1. ## Improper Integral discontinuity

How is this improper? Plug in 1 and it's continuous. Plug in 3 and it's still continuous.

$\int^3_1 \displaystyle\frac{2} {(x-2)^{8/3}} dx$

2. Having $1\le x\le3$ then $x\in[1,3],$ but in this interval, 2 lies there, and $1\le2\le3,$ so there's the discontinuity.