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Thread: Improper Integral discontinuity

  1. October 1st 2008, 03:39 PM #1
    Retromingent
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    Improper Integral discontinuity

    How is this improper? Plug in 1 and it's continuous. Plug in 3 and it's still continuous.

    \int^3_1 \displaystyle\frac{2} {(x-2)^{8/3}} dx
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  2. October 1st 2008, 03:42 PM #2
    Krizalid
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    Having 1\le x\le3 then x\in[1,3], but in this interval, 2 lies there, and 1\le2\le3, so there's the discontinuity.
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