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Math Help - Area between the graphs

  1. #1
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    Area between the graphs

    ok i got the parts where there is a number in the field but im way confused on what it wants for the other ones. Can you help?


    Consider the area between the graphs and . This area can be computed in two different ways using integrals.

    First of all it can be computed as a sum of two integrals
    with the following values:






    Alternatively this area can be computed as a single integral
    with the following values:




    Either way we find that the area is .
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by amiv4 View Post
    ok i got the parts where there is a number in the field but im way confused on what it wants for the other ones. Can you help?


    Consider the area between the graphs and .
    check this. did you really mean to type 1y like that?
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    its an online assignment so i just copied it straight from there and that is how they have it. I'm not sure why but they do
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by amiv4 View Post
    its an online assignment so i just copied it straight from there and that is how they have it. I'm not sure why but they do
    i will say this. the area between two curves is given by \int (\text{top function} - \text{bottom function})~dx or \int (\text{right function} - \text{left function})~dy

    so draw the two curves and see what these functions are and the limits of integration they carry
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    k i got all the information on the first part, but then on the second part i only have the bottom limit of the integral which is -5 but idk wat the top limit is. Cuz i tried 11 and 20 and those dont work and idk wat else it could be
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    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by amiv4 View Post
    k i got all the information on the first part, but then on the second part i only have the bottom limit of the integral which is -5 but idk wat the top limit is. Cuz i tried 11 and 20 and those dont work and idk wat else it could be
    you had to solve 15 - y = y^2 - 5 \implies y^2 + y - 20 = 0 \implies (y + 5)(y - 4) = 0 \implies y = -5 \mbox{ or } y = 4
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    oh ok i get it now. thanks
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