ANSWERS
a.
1125 joules
b. about 21,446,605 j
i am at a utter lost for words.
i m stuck on both of these please help..
a.
If a force of 90 N stretches a spring 1 m beyond its natural length. how much work does it take to stretch the spring 5 m beyond its natural length?
b.
to design the interior surface of a huge staiinless-steel tank, you revolve the curve y = x^2, 0 <= x <= 4, about the y axis. the container with dimensions in meters, is to be filled with seawater, which weighs 10,000N/m^3. how much work will it take to empty the tank by pumping the water to the tanks top??
This is an application of Hookes law that says .
We're initially told that it takes a force of 90 N to stretch it 1 m. This gives us enough info to find k, the spring constant:
Thus, .
Therefore, the total amount of work done to stretch it to 5 m is
Can you take it from here?
I don't have much time to do this one. I will come back later, if no one else has answered this.b.
to design the interior surface of a huge staiinless-steel tank, you revolve the curve y = x^2, 0 <= x <= 4, about the y axis. the container with dimensions in meters, is to be filled with seawater, which weighs 10,000N/m^3. how much work will it take to empty the tank by pumping the water to the tanks top??
--Chris
here is what i did for b.. the right answer is 21 mil, i got 17mil
to design the interior surface of a huge staiinless-steel tank, you revolve the curve y = x^2, 0 <= x <= 4, about the y axis. the container with dimensions in meters, is to be filled with seawater, which weighs 10,000N/m^3. how much work will it take to empty the tank by pumping the water to the tanks top??
anyone have a clue??