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Math Help - Problem involving work

  1. #1
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    Problem involving work

    The cylinder stands vertically. Radius = 4. Height = 20. The water level is 12. Weight of water = 62.4
    The question is to determine how much work is need to drain the water from the cylinder.

    My integral is:
    Int(between 0 and 8). 62.4(pi(4)^2)(20-x)
    When I solved this out i got 127795.2 pi

    I just wanted to know if I did this right.
    Last edited by PensFan10; September 30th 2008 at 03:54 PM. Reason: forgot to put question
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  2. #2
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    if all the water is being pumped to the top of the tank, limits of integration should be from 0 to 12 ...

    W = 62.4 \cdot 16\pi \int_0^{12} (20-y) \, dy
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  3. #3
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    doh

    i was trying to follow some problems i found. i accidentally used the height on a diff problem. thank you
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