Thread: Chain Rule

We are supposed to differentiate the given function and simplify the answer. I'm not sure if I did this correctly.

F(x) = (1-2x)^2/(3x+1)^3

I proceeded this way:
(3x+1)^3(2)(1-2x) - (1-2x)^2(3)(3x+1)^2(3)=

(3x+1)^2(1-2x)[2(3x+1)-9(1-2x)] =

(3x+1)^2(1-2x)[(6x+2)-(9-18x)]

(3x+1)^2(1-2x)(24x-7)

Hello, Becky!

Sorry, you made two omissions in the first step . . .

I proceeded this way:

3x+1)^3(2)(1-2x)" alt="f'(x)\:=\3x+1)^3(2)(1-2x)" />(-2)
. . . . . . . . . . all over denominator-squared

It should have looked like this:
. .

. . . . . .


Factor: .

. . . . . . .

. . . . . . .