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    derivative functions

    y= 1/x find dy/dx
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  2. #2
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    Quote Originally Posted by vinson24 View Post
    y= 1/x find dy/dx
    If y=x^n then \frac{dy}{dx} = nx^{n-1}.

    Here y=\frac{1}{x}. Keep in mind, x \neq 0

    Do you remember your index laws? One is a^{-n} = \frac{1}{a^n}.

    Using this index law, we turn the function into

    y = x^{-1}.

    So the derivative is \frac{dy}{dx} = -1 x^{-2} = -\frac{1}{x^2}. Clearly, once again, x \neq 0.
    Last edited by Prove It; September 28th 2008 at 04:36 PM.
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